Optimal. Leaf size=138 \[ \frac{1}{3} d x^3 \left (a+b \cosh ^{-1}(c x)\right )+\frac{1}{5} e x^5 \left (a+b \cosh ^{-1}(c x)\right )-\frac{b x^2 \sqrt{c x-1} \sqrt{c x+1} \left (25 c^2 d+12 e\right )}{225 c^3}-\frac{2 b \sqrt{c x-1} \sqrt{c x+1} \left (25 c^2 d+12 e\right )}{225 c^5}-\frac{b e x^4 \sqrt{c x-1} \sqrt{c x+1}}{25 c} \]
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Rubi [A] time = 0.121313, antiderivative size = 138, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 5, integrand size = 19, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.263, Rules used = {5786, 460, 100, 12, 74} \[ \frac{1}{3} d x^3 \left (a+b \cosh ^{-1}(c x)\right )+\frac{1}{5} e x^5 \left (a+b \cosh ^{-1}(c x)\right )-\frac{b x^2 \sqrt{c x-1} \sqrt{c x+1} \left (25 c^2 d+12 e\right )}{225 c^3}-\frac{2 b \sqrt{c x-1} \sqrt{c x+1} \left (25 c^2 d+12 e\right )}{225 c^5}-\frac{b e x^4 \sqrt{c x-1} \sqrt{c x+1}}{25 c} \]
Antiderivative was successfully verified.
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Rule 5786
Rule 460
Rule 100
Rule 12
Rule 74
Rubi steps
\begin{align*} \int x^2 \left (d+e x^2\right ) \left (a+b \cosh ^{-1}(c x)\right ) \, dx &=\frac{1}{3} d x^3 \left (a+b \cosh ^{-1}(c x)\right )+\frac{1}{5} e x^5 \left (a+b \cosh ^{-1}(c x)\right )-\frac{1}{15} (b c) \int \frac{x^3 \left (5 d+3 e x^2\right )}{\sqrt{-1+c x} \sqrt{1+c x}} \, dx\\ &=-\frac{b e x^4 \sqrt{-1+c x} \sqrt{1+c x}}{25 c}+\frac{1}{3} d x^3 \left (a+b \cosh ^{-1}(c x)\right )+\frac{1}{5} e x^5 \left (a+b \cosh ^{-1}(c x)\right )-\frac{1}{75} \left (b c \left (25 d+\frac{12 e}{c^2}\right )\right ) \int \frac{x^3}{\sqrt{-1+c x} \sqrt{1+c x}} \, dx\\ &=-\frac{b \left (25 c^2 d+12 e\right ) x^2 \sqrt{-1+c x} \sqrt{1+c x}}{225 c^3}-\frac{b e x^4 \sqrt{-1+c x} \sqrt{1+c x}}{25 c}+\frac{1}{3} d x^3 \left (a+b \cosh ^{-1}(c x)\right )+\frac{1}{5} e x^5 \left (a+b \cosh ^{-1}(c x)\right )-\frac{\left (b \left (25 c^2 d+12 e\right )\right ) \int \frac{2 x}{\sqrt{-1+c x} \sqrt{1+c x}} \, dx}{225 c^3}\\ &=-\frac{b \left (25 c^2 d+12 e\right ) x^2 \sqrt{-1+c x} \sqrt{1+c x}}{225 c^3}-\frac{b e x^4 \sqrt{-1+c x} \sqrt{1+c x}}{25 c}+\frac{1}{3} d x^3 \left (a+b \cosh ^{-1}(c x)\right )+\frac{1}{5} e x^5 \left (a+b \cosh ^{-1}(c x)\right )-\frac{\left (2 b \left (25 c^2 d+12 e\right )\right ) \int \frac{x}{\sqrt{-1+c x} \sqrt{1+c x}} \, dx}{225 c^3}\\ &=-\frac{2 b \left (25 c^2 d+12 e\right ) \sqrt{-1+c x} \sqrt{1+c x}}{225 c^5}-\frac{b \left (25 c^2 d+12 e\right ) x^2 \sqrt{-1+c x} \sqrt{1+c x}}{225 c^3}-\frac{b e x^4 \sqrt{-1+c x} \sqrt{1+c x}}{25 c}+\frac{1}{3} d x^3 \left (a+b \cosh ^{-1}(c x)\right )+\frac{1}{5} e x^5 \left (a+b \cosh ^{-1}(c x)\right )\\ \end{align*}
Mathematica [A] time = 0.101433, size = 101, normalized size = 0.73 \[ \frac{1}{225} \left (15 a x^3 \left (5 d+3 e x^2\right )-\frac{b \sqrt{c x-1} \sqrt{c x+1} \left (c^4 \left (25 d x^2+9 e x^4\right )+2 c^2 \left (25 d+6 e x^2\right )+24 e\right )}{c^5}+15 b x^3 \cosh ^{-1}(c x) \left (5 d+3 e x^2\right )\right ) \]
Antiderivative was successfully verified.
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Maple [A] time = 0.01, size = 115, normalized size = 0.8 \begin{align*}{\frac{1}{{c}^{3}} \left ({\frac{a}{{c}^{2}} \left ({\frac{{c}^{5}{x}^{5}e}{5}}+{\frac{{c}^{5}{x}^{3}d}{3}} \right ) }+{\frac{b}{{c}^{2}} \left ({\frac{{\rm arccosh} \left (cx\right ){c}^{5}{x}^{5}e}{5}}+{\frac{{\rm arccosh} \left (cx\right ){c}^{5}{x}^{3}d}{3}}-{\frac{9\,{c}^{4}e{x}^{4}+25\,{c}^{4}d{x}^{2}+12\,{x}^{2}{c}^{2}e+50\,{c}^{2}d+24\,e}{225}\sqrt{cx-1}\sqrt{cx+1}} \right ) } \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.14329, size = 188, normalized size = 1.36 \begin{align*} \frac{1}{5} \, a e x^{5} + \frac{1}{3} \, a d x^{3} + \frac{1}{9} \,{\left (3 \, x^{3} \operatorname{arcosh}\left (c x\right ) - c{\left (\frac{\sqrt{c^{2} x^{2} - 1} x^{2}}{c^{2}} + \frac{2 \, \sqrt{c^{2} x^{2} - 1}}{c^{4}}\right )}\right )} b d + \frac{1}{75} \,{\left (15 \, x^{5} \operatorname{arcosh}\left (c x\right ) -{\left (\frac{3 \, \sqrt{c^{2} x^{2} - 1} x^{4}}{c^{2}} + \frac{4 \, \sqrt{c^{2} x^{2} - 1} x^{2}}{c^{4}} + \frac{8 \, \sqrt{c^{2} x^{2} - 1}}{c^{6}}\right )} c\right )} b e \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 2.40362, size = 271, normalized size = 1.96 \begin{align*} \frac{45 \, a c^{5} e x^{5} + 75 \, a c^{5} d x^{3} + 15 \,{\left (3 \, b c^{5} e x^{5} + 5 \, b c^{5} d x^{3}\right )} \log \left (c x + \sqrt{c^{2} x^{2} - 1}\right ) -{\left (9 \, b c^{4} e x^{4} + 50 \, b c^{2} d +{\left (25 \, b c^{4} d + 12 \, b c^{2} e\right )} x^{2} + 24 \, b e\right )} \sqrt{c^{2} x^{2} - 1}}{225 \, c^{5}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 3.01693, size = 178, normalized size = 1.29 \begin{align*} \begin{cases} \frac{a d x^{3}}{3} + \frac{a e x^{5}}{5} + \frac{b d x^{3} \operatorname{acosh}{\left (c x \right )}}{3} + \frac{b e x^{5} \operatorname{acosh}{\left (c x \right )}}{5} - \frac{b d x^{2} \sqrt{c^{2} x^{2} - 1}}{9 c} - \frac{b e x^{4} \sqrt{c^{2} x^{2} - 1}}{25 c} - \frac{2 b d \sqrt{c^{2} x^{2} - 1}}{9 c^{3}} - \frac{4 b e x^{2} \sqrt{c^{2} x^{2} - 1}}{75 c^{3}} - \frac{8 b e \sqrt{c^{2} x^{2} - 1}}{75 c^{5}} & \text{for}\: c \neq 0 \\\left (a + \frac{i \pi b}{2}\right ) \left (\frac{d x^{3}}{3} + \frac{e x^{5}}{5}\right ) & \text{otherwise} \end{cases} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.2535, size = 194, normalized size = 1.41 \begin{align*} \frac{1}{3} \, a d x^{3} + \frac{1}{9} \,{\left (3 \, x^{3} \log \left (c x + \sqrt{c^{2} x^{2} - 1}\right ) - \frac{{\left (c^{2} x^{2} - 1\right )}^{\frac{3}{2}} + 3 \, \sqrt{c^{2} x^{2} - 1}}{c^{3}}\right )} b d + \frac{1}{75} \,{\left (15 \, a x^{5} +{\left (15 \, x^{5} \log \left (c x + \sqrt{c^{2} x^{2} - 1}\right ) - \frac{3 \,{\left (c^{2} x^{2} - 1\right )}^{\frac{5}{2}} + 10 \,{\left (c^{2} x^{2} - 1\right )}^{\frac{3}{2}} + 15 \, \sqrt{c^{2} x^{2} - 1}}{c^{5}}\right )} b\right )} e \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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